What is the point-slope equation of the line through the point (–5, 5) that is perpendicular to the line whose equation is 5x = 3y?
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There are several ways to find a equation of a line that satifies some conditions. I'll go with the least theory heavy. A line can be represented as \[y=mx+b\] Where "m" represents the slope and "b" the y-interception. Another tool you might want to use is the condition of perpendicularity: \[m_1 m_2 = -1\] or if you prefer: \[m_1 = -\frac{ 1 }{ m_2 }\] This just means, that in order for a slope "1" to be perpendicular to a seconde slope "2", it has to be reciprocal and opoosite to the slope "1".
|dw:1428657046242:dw| always draw a plot of what you know it makes things clear
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