compare V=Vo exp^(-t/RC) by straight line equation y=mx+c

Question

dominantvampire · Answer

kindly help, i shall medal

dominantvampire · Answer

where RC and Vo are constants

dominantvampire · Answer

what are the dependent  independent variable

kainui · Answer

I'm not entirely sure what you're asking, but I'm assuming you want to turn this exponential into log-linear form.

dominantvampire · Answer

yes ofcourse

kainui · Answer

Ok, so first thing we need to do is take the natural log of both sides of this equation to get it in that form and use some log rules, can you do that?

dominantvampire · Answer

suppose in an experiment the potential difference, V across a discharging capacitor is measured as the function as a time, t. the relation b.w V and  is given by
V=Vo exp^(-t/RC)

dominantvampire · Answer

lets see

dominantvampire · Answer

no, i cannot

kainui · Answer

Well let's start here, take the natural log of both sides: $$\Large \ln(V)=\ln(V_0 e^{-t/RC})$$ Now we can use log rules on the term on the right since they're multiplied together we can separate them into the sum: $$\Large \ln(V)=\ln(V_0) + \ln( e^{-t/RC})$$ Can you simplify that right most term?

dominantvampire · Answer

i can, i shall take it from here, thankyou