Question

Using a balanced equation for the synthesis reaction between Sodium metal and Chloriine gas: Calculate how many grams of Salt may be produced from a 5.00 gram sample of solid sodium metal when combined with unlimited Chlorine gas.

Answer 1

you need to turn those names into proper chemical formulas, then balance the reaction

Answer 2

I really.. just don't know how to do Stoichiometry :(

Answer 3

2 Na + Cl2 → 2 NaCl

(5.00 g Na) / (22.98977 g Na/mol) x (2 mol NaCl / 2 mol Na) x (58.4430 g NaCl/mol) = 12.7 g NaCl

Answer 4

the diamond thing is supposed to be an arrow

Answer 5

Woah! how did you do that ? :/

Answer 6

Using your balanced equation from question 1 and the amount 5.00 grams of Sodium metal, Calculate

a. How many moles of Chlorine gas would be used up.

b. how many Liters of Chlorine gas would be used in the reaction if the reaction took place at STP. Key to solving this is to know that 1 mole of gas at STP is 22.4 Liters.

Answer 7

its pretty simple, you just take the numerical amount thats given, which in this case is 5 g of sodium. then you look at a periodic table and youll see that sodium (Na) has a molar mass of 22.99so you take 5 g Na / 22.99 g Na/mol. then you have to do the mol : mol ration which you see in the balanced equation. so there are 2 mols of NaCl, and 2 mols of Na. then you find the molar mass of NaCl by looking at the molar mass of each element of the periodic table. (Na = 22.99 Cl = 35.45) you add those together and multiply them all then divide them. its kind of hard to show you on here, but i can make a word doc with each step if you want?

Answer 8

Thank you so much!! you explain it easier than my teacher -_-