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Geometry 15 Online
OpenStudy (anonymous):

1. Find the equation of the tangent lines to the circle x^2+ y^2 + 6x - 2y+5=0, perpendicular to the line 2x +y = 4. Draw the Figure. somebody can answer this deserve a medal and fan :D , i want you to show the figure and the answer

OpenStudy (solomonzelman):

if your line is supposed to be perpendicular to 2x+y=4, can you tell me the slope of your new line ?

OpenStudy (solomonzelman):

(by new line I am referring to the tangent line)

OpenStudy (solomonzelman):

and I will tell you you will have 2 points with such slope.

OpenStudy (solomonzelman):

and therefore 2 tangent lines.

OpenStudy (anonymous):

can you show me the figure first :D

OpenStudy (solomonzelman):

don't understand you

OpenStudy (anonymous):

the slope of the new line is 1/2

OpenStudy (solomonzelman):

yes, correct.

OpenStudy (solomonzelman):

https://www.desmos.com/calculator/l6aipy5fys

OpenStudy (solomonzelman):

I am just curious, this is calculus I, right >?

OpenStudy (anonymous):

its analytic geometry, its my major subject and i think im going to gave up with it... -.-

OpenStudy (solomonzelman):

well you can visualize it, without proofs

OpenStudy (solomonzelman):

where do you think are the 2 points on a circle, where the tangent line's slope is 1/2 ?

OpenStudy (anonymous):

|dw:1428514869444:dw|

OpenStudy (solomonzelman):

your two points seem to be (-4,3) and (-2,1)

OpenStudy (solomonzelman):

and your slope for both lines is 1/2

OpenStudy (solomonzelman):

so line 1: point (-4,3) , slope 1/2 line 2: point (-2,1) , slope 1/2

OpenStudy (anonymous):

how did you get that points?

OpenStudy (anonymous):

can you help me dude

OpenStudy (solomonzelman):

I visualized those points

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