Ask your own question, for FREE!
Physics 21 Online
OpenStudy (anonymous):

What formula would I use for this? A 10cm-radius, 25-loop circular wire coil with 40 ohms of resistance sits in a 50T magnetic field. Over the next eight seconds, the field strength is reduced by one-fifth. If the field strength is reduced during a two-second time interval instead, how much current would flow in the coil? Other information: 0.98V induced in the coil, 0.025A flows in the coil while the field is being reduced.

OpenStudy (anonymous):

You gotta use Faraday's law \[emf = -L \frac{di}{dt}\]

OpenStudy (anonymous):

I am so sorry It is \[emf = -NA \frac{dB}{dt}\]

OpenStudy (anonymous):

So which of these numbers would I use? I get confused

OpenStudy (irishboy123):

it's a really daft question. they give you the answer to the first bit (or did you work that out? if so, it's right, BTW) , so the question really is this -- if you change the field strength 4 times as fast (ie over 8s rather than 2s), what does that do to the induced current and voltage, given previosu figures of 0.98V and 0.025A induced ? do you know the answer to that?

OpenStudy (anonymous):

I worked out the first problems myself. But would I multiply the .025A by 4? And get .1A for my answer?

OpenStudy (irishboy123):

yes, it's all happening 4x faster so go for it.

OpenStudy (anonymous):

It's right! Thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!