3. Light coming from a fish makes an incidence angle of 30° to normal under the water. The index of refraction of water is 1.33. A fisherman is looking at the fish through air. At what angle with the normal (θr) will the fish appear to the fisherman? Use Snell’s law: nisinθi = nrsinθr.

Question

3.	Light coming from a fish makes an incidence angle of 30° to normal under the water. The index of refraction of water is 1.33. A fisherman is looking at the fish through air. At what angle with the normal (θr) will the fish appear to the fisherman? Use Snell’s law: nisinθi = nrsinθr.

aaronq · Answer

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$\sf \huge   sin\theta_{water }\eta _{water }=sin\theta_{air  }\eta _{air  }$

$\sf \huge  \theta_{air}=sin^{-1}(\dfrac{ sin\theta_{water }\eta _{water }}{\eta _{air  }}) $