Question

Find the length of the arc s in the figure. (Assume r = 9 and θ = 126°.)

Answer 1

Hint

\[\large s = r\theta\]

Answer 2

Here is a picture of the figure

Answer 3

I know the formula but every time I try it it says the answer is incorrect @johnweldon1993

Answer 4

What have you used for the answer input?

Answer 5

well I converted the degrees into radians to get 7pi/10 then I input the 9

Answer 6

into the formula

Answer 7

And you get 19.79 right? hmm interesting, hang on a sec

Answer 8

Hmm I'm not sure, that IS the correct answer, not sure why it isn't being accepted

Answer 9

Omg -_-

Answer 10

Alright, so it's obvious I shouldnt be in engineering because I missed this -_-

Answer 11

So using what we were doing...we needed to realize that



s = r(theta) gives us the arc length that in enclosed by those lines...

But the question is asking for the length of everything BUT that section -_-

Answer 12

So instead of using THAT angle...we need to use

Answer 13

lol yeah i know I just realized it too

Answer 14

do you know how to solve for that?

Answer 15

\(\large {
\textit{arc's length}=s=\cfrac{r\theta\pi }{180}\quad
\begin{cases}
r\to radius\\
\theta=\textit{angle in degrees}
\end{cases}
}\)

Answer 16

isnt that the same thing as s= theta r?

Answer 17

@jdoe0001

Answer 18

hmmm "s" is just "the arc's length", just the notation, is all

Answer 19

i got 11.7 times pi?

Answer 20

or \(\large {
\textit{arc's length}=\cfrac{r\theta\pi }{180}\quad
\begin{cases}
r\to radius\\
\theta=\textit{angle in degrees}
\end{cases}
}\)