write an explicit formula for each geometric sequence. Then generate the first five terms. a1=6, r=2 @sissyedgar
\(\large\color{black}{ \displaystyle a_1=6 }\) \(\large\color{black}{ \displaystyle r=2 }\) \(\large\color{black}{ \displaystyle a_2=6\times 2=12 }\) \(\large\color{black}{ \displaystyle a_3=12 \times 2=24 }\)
and on...
but what is the explicit formula for this equation @SolomonZelman
well \(\large\color{black}{ \displaystyle a_n=\left(a_1\right)\times({\rm r})^{n-1} }\)
use, \(\large\color{black}{ \displaystyle a_n=\left(a_1\right)\times({\rm r})^{n-1} }\) but in your case, \(\large\color{black}{ \displaystyle a_n=\left(6\right)\times({\rm 2})^{n-1} }\)
\[\sum_{n=1}^{5} (2n+3)\] @SolomonZelman
find the sum of each finite series
no, that is a series
that is the sum of all terms
\(\large\color{black}{ \displaystyle \left\{6\times 2^{n-1}\color{white}{\Huge|}\right\}_{n=1}^{\infty} }\)
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