MEDAL! Yvonne put $4,000 into a savings account. At the end of 3 years, the account had earned $960 simple interest. How many more dollars would she have in her account if the interest rate were 1% greater? Help Please!
@campbell_st
the interest rate is 8%
so 1st you need to find the rate of interest, so use the information you are given formula is I = Prn you know I = 960, P = 4000 and n = 3 so \[960 = 12000r~~~or ~~~r = \frac{960}{12000}\] find r..
that will be a decimal value for r, multiply it by 100 to get the percentage value. then add 1 to the answer to find the extra money use the new interest rate as a decimal in the formula with P still 4000 and n still 3 hope it helps
wait what formula do I use?
simple interest I = Prn or I = Prt I = interest, P = Principal, r = interest rate as a decimal n or t = time periods.
so like this? 960=1200*0.09
well.. we dunno what her interest rate is thus, we'd want to know that first thus \(\bf \qquad \textit{Simple Interest Earned}\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\to &\$960\\ P=\textit{original amount deposited}\to& \$4000\\ r=rate\\ t=years\to &3 \end{cases} \\ \quad \\ 960=4000\cdot r\cdot 3\impliedby \textit{solve for "r"}\)
well the thing is I already solved for the interest rate which is 8% and its telling me to add 1% to the interest rate (8%) which all together would be 9%.
right.... so.... you yes.. then you're correct is \(\bf 960=1200*0.09 \) then find the difference between both amounts
hmmm wait a sec....
we know the rate is 8% + 1% = 9% we dunno what the earned interest is so should just be \(\bf i=1200*0.09 \)
well... we're missing he years... so... hmm \(\bf i=1200*0.09 * 3\)
wait what do we need earned interest for?
and the years is the 3
well.. at 8%, on a principal of 12,000 over 3 years she's got an earned interest of 960 so...you're asked how much more, would she had now, had it been 9% instead of 8%? so.... find how much is at 8%, we know that, 960 find how much is at 9%, we dunnno that then get their difference and that's how much she would have gottent more, had she been using 9% from the beginning
I am confused a little, can you set up the equation to plug In the 9% instead of the 8%?
hmmm actually, above I used 12,000, should have been 4000.... but anyway just to clear that out
ok, can you show me the equation to find how much Yvonne will have in her account if she had 9% as her interest rate?
\(\bf \qquad \textit{Simple Interest Earned}\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\to &\$960\\ P=\textit{original amount deposited}\to& \$4000\\ r=rate\\ t=years\to &3 \end{cases} \\ \quad \\ 960=4000\cdot r\cdot 3\impliedby r=8\% \\ \quad \\ \quad \\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$4000\\ r=rate\to &0.09\\ t=years\to &3 \end{cases} \\ \quad \\ I=4000\cdot 0.09\cdot 3\impliedby r=9\%\)
I=1080 but that cant be right if her total amount of money in her account is 4,960
1080 is the "earned interest" NOT her account total balance is just the interest earned on the 4000, so the full balance of her account will be 4000+ 1080 at 9% her total account balance will be 4000 + 960 at 8%
if you put $100 in the bank and they pay you 10% after a year that means the earned interest is 10% of 100, or $10 that doesn't mean you put in $100, and after a year you ended up with $10 or $90 less.... simply means, you started with 100, and now added 10 more to it, or 110
ok now im very confused, can you set up the equation that will show how much Yvonne will have in her account if she had 9% as her interest rate?
as clear as possible
hmm those are above... can't get clearer I'd think do you even know what an earned interest amount is?
no, I had not learned about this yet
well... earned interest is amount extra, from the original amount
oh! wait I do know what it is I just forgot :p
you're asked ok, she made 960 at what rate? you found 8% so at 8% she made 960 at 9% she made how much? what's the difference between the two amounts? or how much would she had made more, had she used 9% instead of 8%
I know but I don't know how to solve that, that is the reason why I asked this question
well.. how did you get the 8% for the rate? you'd get the "i" for the 2nd rate of 9%, using the same "simple interest formula"
\(\bf \qquad \textit{Simple Interest Earned}\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\to &\$960\\ P=\textit{original amount deposited}\to& \$4000\\ r=rate\\ t=years\to &3 \end{cases} \\ \quad \\ 960=4000\cdot r\cdot 3\impliedby r=8\% \\ \quad \\ \quad \\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$4000\\ r=rate\to &0.09\\ t=years\to &3 \end{cases} \\ \quad \\ I=4000\cdot 0.09\cdot 3\impliedby r=9\%\)
I got 8% for the rate by using the formula to find the rate --- A=1/P*T *100
well... you got 1080 already from the 9%, right? so.. we know at 8% she earned 960 we also know at 9% she earned 1080 so 1080 - 960 = " how much MORE she would have gotten, had she used 9%"
ok now this makes much more sense
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