Question

find both coordinates of the vertex of thenparabola g(x)=-2x^2+2x-5

Answer 1

Having a function F(x) = ax^2 + bx + c
You can find the parabola:
V ( -B/2A , F(-B/2A))

Answer 2

re-type the question.

Answer 3

g(x)=-2x^2+2x-5

Answer 4

find the axis of symmetry first

Answer 5

how

Answer 6

well, for a parabola in the form ax^2+bx+c, it is x=-b/2a

Answer 7

thankyou

Answer 8

what did you get?

Answer 9

1/2

Answer 10

\(\bf \textit{vertex of a parabola}\\ \quad \\
g(x) = {\color{red}{ -2}}x^2{\color{blue}{ +2}}x{\color{green}{ -5}}\qquad

\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)

Answer 11

ok, now plug that in for x, into the equation and tell me what you get

Answer 12

or do as Rizags suggested

Answer 13

-9/2

Answer 14

yes, correct, now the vertex will be (x, g(x)), or \[(\frac{1}{2}, -\frac{9}{2})\]

Answer 15

thank you so much

Answer 16

yup, no prob