Question

The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times.

What is the experimental probability of rolling a 3 or a 6?

Express your answer in simplest form.

outcome 1 2 3 4 5 6
# of outcomes 10 6 4 8 6 6

I know the answer, it is 7/20, i want to know how it is that

Answer 1

i will give medal and fan :)

Answer 2

plz help anyone!

Answer 3

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Answer 4

plz help, as u can see, i am desperate

Answer 5

i got u

Answer 6

thank u oh so much

Answer 7

u got the right answer just let me work it out really quick ok

Answer 8

okay

Answer 9

so u got 7 from how many times u through the dice

Answer 10

oh, really

Answer 11

@amistre64 hey can u help me really quick bro

Answer 12

it is 6, is it not

Answer 13

anyhoo, how did u get the 20 part?

Answer 14

idk bro

Answer 15

@zepdrix help me plz, i see u viewing the question

Answer 16

:3

Answer 17

u r smart, plz help @zepdrix

Answer 18

\/ out yo

Answer 19

huh

Answer 20

I'm not sure where 7/20 is coming from...
That doesn't seem correct.

A 3 was rolled \(\Large\rm 4\) times.
A 6 was rolled \(\Large\rm 6\) times.

So the experiment showed that a 3 or 6 was rolled \(\Large\rm 4+6\) times, yes?

Answer 21

ok

Answer 22

What is that in relation to the TOTAL number of rolls?

Answer 23

ummmmm...

Answer 24

What is the total number of rolls? :)
(Add the bottom numbers)

Answer 25

oh, i get so, i know how 20 is, u add up all of the # of outcomes

Answer 26

i am not sure how u get 7 thoug, plz help!

Answer 27

You should get 40 when you add all of those up, not 20.

So your experimental probability of rolling a 3 or 6 would be \(\Large\rm \frac{10}{40}\).

Again, I don't know where this 7/20 is coming from. Hmm..

Answer 28

i get 40 divided by 2 is 20, hmmm...

Answer 29

yolo, anyone there

Answer 30

@roycekimmons

Answer 31

plz help

Answer 32

@Michalsss

Answer 33

Out of 1 through 6

You have 1/6 of a chance to roll a 3
And another 1/6 chance to roll a 6

So add that up, and you should have your answer.