Question

(x^1/3+y^-2/3)(x^4/3-y^-1/3)

Answer 1

@TheSmartOne

Answer 2

what are you asking for here?

Answer 3

I have to perform the operation like multiply it but and i'm stuck with the whole exponent fractions. Like i foiled but i feel like you can add the middle numbers o.o

Answer 4

Show me what you have so far

Answer 5

ok now show what you have do far with the expanding

Answer 6

thats a correct expansion, i mean you cant add those middle terms in their current state, so I'd say thats fully correct

Answer 7

:o how come you can't add em

Answer 8

becuz they have different exponents

Answer 9

you cant just add x^2 to x, for example

Answer 10

but don't they have the same denominator in the exponents like when you multiply the first term.

Answer 11

well, yes, they do, but you still cannot add them unless the exponents are exactly the same, like you can add x^2 and x, or y^1/3 and y^2/3

Answer 12

*can't

Answer 13

Oh alright lol and i have at least two other problems :o mind helping?

Answer 14

sure i'll help! fan plz if you want

Answer 15

Of course!

Answer 16

Okay the question is m^2/3/m^-8/5 my answer was m^-6 but on the board it said m^2 :o

Answer 17

is this the problem: \[\frac{m^{\frac{2}{3}}}{m^{\frac{-8}{5}}}\]

Answer 18

Yessss

Answer 19

wait is it since we have to divide you got to subtract therefore you gotta change the sign o.o?

Answer 20

well, it becomes \[\huge\frac{ 2 }{ 3 }-\frac{ -8 }{ 5 }\]

Answer 21

or, \[\large\frac{2}{3}+\frac{8}{5}\]

Answer 22

oh wait my bad the first fraction is 2/5

Answer 23

not 2/3

Answer 24

ok, so its just \[\huge m^{\frac{2}{5}+\frac{8}{5}}\] can you solve that?

Answer 25

yes 10/5 reducing to 2 which equals m^2 :)

Answer 26

riiiiiiiite

Answer 27

Thank you now the other question i don't know how to start

Answer 28

um, this isn't really a "solvable" thing so to speak.

Answer 29

what you mean?

Answer 30

like, what exactly are you supposed to do with this? simplify?

Answer 31

I don't know it says perform the operation it's in the same section as the ones we did

Answer 32

i mean, i suppose you could rewrite it like this: \[\huge \frac{\frac{1}{a^2}+\frac{b}{a}-b^2}{\frac{a^2}{b}}\]

Answer 33

that's kinda confusing o.o

Answer 34

ur rite xD ummmmm what class is this for?

Answer 35

Algebra 2 lol

Answer 36

i'm also in algebra 2 xD but this does not look simplifiable to me

Answer 37

It's a test review and i'm like so lost in that one but thank you so much for your help :) if i have another question can i tag u ?

Answer 38

yes ofc!

Answer 39

Thank you :)

Answer 40

np :)