Question

So I'm stuck...

Answer 1

\[x^2-14x+43=0\]
I subtracted and got \[x^2-14x=-43\]
and then did (\[(-14/2)^2 = 49\]
but when i subtract it from both sides I get (-43-49) = -92
but you can't have a negative square root.. what did I do wrong?

Answer 2

add 49 on both sides

Answer 3

Okay! So if it's positive you write it down as subtracting?

Answer 4

you will always add that ( b/2)^2 thingy to both sides
no subractys

Answer 5

OH OKAY I THINK I GOT IT NOW! (sorry I'm excited)

Answer 6

So I added and got
\[x^2-14x=\sqrt{6}\]

so the form would be \[(x-7)^2=6\]
and then I did \[\pm \sqrt{6}+7 = 9.44, 4.56\]

Answer 7

wow you did it

Answer 8

good job

Answer 9

I'm so happy, the struggle to understand this was insane! Thank you so much, I wouldn't have been able to do it without you.

Answer 10

np

Answer 11

and also fantastic job
and keep up the good work :)