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Calculus1 18 Online
OpenStudy (anonymous):

How do I do this? Limits at infiinity?

OpenStudy (anonymous):

\[\lim_{x \rightarrow \infty}\ln(1+x)-\ln(x)\]

OpenStudy (amistre64):

simplify the right side using log rules

OpenStudy (amistre64):

then , divide every term by the highest power of x that exists in the setup; anything that has an x left under it goes to zero, the limit is whats left over.

OpenStudy (amistre64):

i spose we could technically just split the fraction and it tuns into 1 + 1/x but thats just to simple to say lol

OpenStudy (jhannybean):

Can you also use conjugates?

OpenStudy (amistre64):

im not sure if thats useful here. conjugates tend to be a form of multiplying by 1 (a-b)/(a-b)

OpenStudy (amistre64):

ln(a) - ln(b) = ln(a/b) after that, theres a few ways to consider it. same degree polys, splitting the fraction, dividing terms by highest power x, etc ....

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