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OpenStudy (anonymous):
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OpenStudy (anonymous):
Question?
OpenStudy (anonymous):
Tag me when you are ready and I can see if I can help :)
OpenStudy (anonymous):
so if your given something like
OpenStudy (anonymous):
\[((3t^2-5)(10)-(1+2t)(12t))/ (3t^2-5)^3 \]
could you just cancel out the 3t^2 -5 ? which would make (3t^2-5)^2 at the bpottom?
OpenStudy (anonymous):
im saying no, because the numbers after the minus sign dont have a 3t^2-5?
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OpenStudy (anonymous):
@MSxSammiBooxX
OpenStudy (anonymous):
I am confused as to what you are asking?
OpenStudy (anonymous):
like can i cancel the 3t^2-5 in the numerator and the denominator?
OpenStudy (anonymous):
Ok, so you have \(\dfrac{(3t^2-5)(10)-(1+2t)(12t)}{3t^2-5^3}\)
You would have to simplify first before you do any canceling
OpenStudy (anonymous):
so basically i catn because simplifying the numerator is not gonna give me 3t^2-5
and oh its not 3t^2-5^3 for the denominator its (3t^2-5)^3
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OpenStudy (anonymous):
If you break up the fraction into two parts you can do it to one part but not the other.
OpenStudy (anonymous):
\[\frac{ (3t-5)(10) }{ (3t-5)^3 }-\frac{ (1+2t)(12t) }{ (3t-5)^3}\]
OpenStudy (anonymous):
if that helps you at all
OpenStudy (anonymous):
oh.... right T>T that didnt cross my head yeah it did
OpenStudy (anonymous):
thank you :)
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OpenStudy (anonymous):
No problem
OpenStudy (anonymous):
when your finding the GCF from lets say |dw:1428557652573:dw|
do you have to take out from each (dont know the right term but here goes) area?
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