Question

Finding the exact value of
Sin[cos^-1(0)]

Answer 1

I know cos=0 At pi/2 and 3pi/2 but not sure where to go from there

Answer 2

cos=x
sin=y

cos=0 at 90 degrees and 270 degrees

Answer 3

so im pretty sure cos^-1 would be...

Answer 4

I forgot.

Answer 5

hint:
\[\large \arccos 0 = \frac{\pi }{2},\;\frac{{3\pi }}{2}\]

Answer 6

Already said I got that far :p

Answer 7

Are you suggesting to simply do sin x pi/2, etc?

Answer 8

hint:
what is
sin(pi/2)=...?
and:
sin(3*pi/2)=...?

Answer 9

OHH

Answer 10

You would convert those radians to degrees first, right? Then use the unit circle?

Answer 11

Sin(pi/2)=0.02741 it's that simple?

Answer 12

Well, see that's the confusing part

sin(90 degrees)

would be 1.

Answer 13

depends on how we convert it.

@Michele_Laino

Answer 14

we have:
sin(pi/2)= sin(90) = 1
and:
sin(3*pi/2)=sin(270)=-1

Answer 15

oh, so we do convert it to degrees. all clear now.

Answer 16

Thanks

Answer 17

thanks!