Question

f(x)= x^2/(2+x)
f'(x)=4x+x^2/((2+x)^2)
How do I go about finding the second derivative?

Answer 1

u know how to differentiate ?

Answer 2

we covered it in class, but I don't really understand it

Answer 3

u can differentiate f(x) two times and u will get second derivative

Answer 4

product rule tends to be simpler to assess

[ab^(-1)]' = a'b^(-1) - a b' b^(-2)

Answer 5

for f'(x)=\[\frac{ 4x+x ^{2} }{ (2+x)^{2} }\]
this is what I got

Answer 6

ugh ... wolf says its bad ... accursed algebra!!

Answer 7

quotient rule:

bt' - b't
------
b^2

Answer 8

why can't math be easy??! haha

Answer 9

\[\frac{ 4x+x ^{2} }{ (2+x)^{2} }\]
\[\frac{ (2+x)^{2}(4x+x ^{2})'- (4x+x ^{2})[(2+x)^{2}]'}{ [(2+x)^{2} ]^2}\]
\[\frac{ (2+x)^{2}(4+2x)- 2(4x+x ^{2})(2+x)}{ (2+x)^{4}}\]
\[\frac{ (2+x)(4+2x)- 2(4x+x ^{2})}{ (2+x)^{3}}\]
and simplify

Answer 10

@mateeldaa do u still need any help?

Answer 11

thank y'all so much!!