write \(\frac{19}{51}\) as continued fraction http://upload.wikimedia.org/math/8/a/7/8a73a8728febba2c2ecb9abc2f4e0d03.png
\[\frac ab=\frac1{b/a}\]
what is 51/19
do i get \[\begin{align}\frac{19}{51} &= 0 + \dfrac{1}{\dfrac{51}{19}}\\~\\&= 0 + \dfrac{1}{2+\dfrac{13}{19}} \end{align}\]
does it have to be an infinite continued fraction
i think continued fraction of every rational number ends because we will eventually get 0 after dividing enough times
\[\frac{19}{51}\] \[\frac{1}{51/19}\] \[\frac{1}{2+13/19}\] \[\frac{1}{2+\frac{1}{19/13}}\] \[\frac{1}{2+\frac{1}{1 +\frac{6}{13}}}\] \[\large \frac{1}{2+\frac{1}{1 +\frac{1}{13/6}}}\] etc ...
oh ok
wow! wish there is some direct formula for getting these coefficients w/o doing so many divisions
what? its the divisions that makes it so fun ....
it is fun for sure xD a generating function or an explicit formula for like : \(a_n = f(n)\)
sometimes its written as the .... addend series? [0:2,1,2,....]
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