Question

Suppose that the probability a seed will germinate is 85%. What is the probability that 7 of these seeds will germinate when 10 are planted?
a.
0.1298
b.
0.385
c.
0.12
d.
0.141

Answer 1

@aaronq

Answer 2

So you have to use the Binominal formula

\(\sf \huge P(k~in~n~trials)= (^n_k)p^kq^{n-k}\)

n = number of trials
k = number of successes
n – k = number of failures
p = probability of success in one trial
q = 1 – p = probability of failure in one trial

for your question

n=trials=10
k=successes=7
n-k=10-7=3
p=85%
q=1-0.85=0.15

\(\sf \huge P(7~in~10~trials)= (^{10}_7)(0.85)^7(0.15)^{3}\)

Answer 3

got a bit cut off at the end
$$\sf \Large P(7~in~10~trials)= (^{10}_7)(0.85)^7(0.15)^{3}$$

Answer 4

is it 10/7 ?

Answer 5

0.1298 ?

Answer 6

@perl thanks

@420chiick yes