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Calculus1 10 Online
OpenStudy (anonymous):

Please check my answer. I got D as shown by the dot Please take a look at the attachment for the problem.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

we have: \[\large y + 5 = {x^3}\]+ so: \[\large x = ...?\]

OpenStudy (michele_laino):

oops...+ is a typo

OpenStudy (anonymous):

x+ \[\sqrt[3]{y+5} = x\]

OpenStudy (anonymous):

oops the x+ is a type, ignore it please

OpenStudy (michele_laino):

oops... I have made an error, sorry. The rigt steps, are: \[\large y + 5 = 3{x^3}\] so: \[\large x = ...?\]

OpenStudy (anonymous):

\[x = \sqrt[3]{y+5}\div \sqrt[3]{3}\]

OpenStudy (michele_laino):

ok! Now we have to replace x with y and y with x, what do you get?

OpenStudy (anonymous):

So basically \[\left(\begin{matrix}x+5 \\3\end{matrix}\right)^1/3\]

OpenStudy (anonymous):

woops thats to the ^1/3

OpenStudy (michele_laino):

ok! \[y = {\left( {\frac{{x + 5}}{3}} \right)^{1/3}}\]

OpenStudy (anonymous):

yes that. lol. Thank you so much!

OpenStudy (michele_laino):

thank you!

OpenStudy (anonymous):

no, you don't have anything to thank me for. I have to thank you.

OpenStudy (michele_laino):

ok! :)

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