Question

Which expression is equivalent to sec2xcot2x?

Answer 1

A. sin^2x
B. csc^2x
C. 1/cos^2x
D. 1/sin^2x

Answer 2

we have to use these identities:
\[\large \begin{gathered}
\sec x = \frac{1}{{\cos x}} \hfill \\
\cot x = \frac{{\cos x}}{{\sin x}} \hfill \\
\end{gathered} \]

Answer 3

ok

Answer 4

you should get this:
\[\large {\left( {\sec x} \right)^2}{\left( {\cot x} \right)^2} = \frac{1}{{{{\left( {\cos x} \right)}^2}}}\frac{{{{\left( {\cos x} \right)}^2}}}{{{{\left( {\sin x} \right)}^2}}} = ...?\]

Answer 5

ok

Answer 6

@matthew1286

Answer 7

note - the (cos x)^2 cancel out

Answer 8

ok, well this still dosent make senese

Answer 9

why ?

Answer 10

i have no idea

Answer 11

the question is a bit confusing
because sec2x could mean 2 different things

- either sec^2x ( which also can be written as (sec x)^2 ) or sec 2x

Answer 12

^ it has that

Answer 13

Ok the Michelle's answer is correct
you just have to cancel out the (cos x)^2 to give you one of the options

Answer 14

ok thanks

Answer 15

yw
just remove the 2 (cos x)^2 and see what you have left