Question

A circle is centered at the point (5, -4) and passes through the point (-3, 2).

Answer 1

The equation of this circle in standard form is (x +____)2 + (y +____)2 =_____

Answer 2

@iGreen @welshfella @Girlamerican16

Answer 3

@shifuyanli

Answer 4

sorry I haven't really got to this yet, I hope you understand :)

Answer 5

its fine

Answer 6

The equation of a circle centered at \((x_0, y_0)\) with radius \(r\):
\[(x - x_0)^2 + (y- y_0)^2 = r^2\]
Use this equation and use the distance formula to solve for the radius:
\[d = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2}\]

Answer 7

oh ok thanks

Answer 8

@iGreen

Answer 9

anybody?

Answer 10

Formule for a circle is
(x-h)^2+(y-k)^2=r^2

Answer 11

Given
h=5
k=-4

Answer 12

r=radius of ur circle

Answer 13

r=distance frm centre of a circle to any point on the circle

Answer 14

So
r=distance frm (5,-4) to the point (-3,2)=?

Answer 15

i still dont get it

Answer 16

Ok. Can u tell me r=?

Answer 17

what do you mean?

Answer 18

r=radius of ur circle

Answer 19

Now u hv to know the formula to calculate the distance

Answer 20

\[r=C/2\]

Answer 21

with pi

Answer 22

Ok.
r=root((5--3)^2+(-4-2)^2)=?