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Write a recursive formula for the explicit formula: A(n)=5+(n-1)(3)
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might help to write out the first 3 or 4 terms to see how its moving ... notice a pattern if you will
What do you mean?
hint: we can write: \[\begin{gathered} {a_1} = 5 \hfill \\ {a_2} = 5 + 3 \times (2 - 1) = 5 + 3 = 8 \hfill \\ {a_3} = 5 + 3(3 - 1) = 5 + 6 = 11 \hfill \\ {a_4} = 5 + 3(4 - 1) = 5 + 9 = 14 \hfill \\ \end{gathered} \]
as you can see, a term is three more of the preceding term
Okay, yeah I see it
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so we can write: \[A\left( n \right) = A\left( {n - 1} \right) + ...?\]
please complete my formula
3?
that's right!
Thanks!
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Thanks!
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