Question

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.

What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

P(red and yellow) ≈__________ %

Answer 1

P(event 1 followed by event 2) = P(event1) * P(event 2)

Answer 2

No, not P(red and yellow), rather P(first red and then yellow)

How may red?
How many total?
The first part nearly is done.

Answer 3

Event 1 is drawing a red marble out of all marbles.
Find the probability of event 1.

Event 2 is drawing a yellow marble out of all _remaining_ marbles.
What is the probability of event 2?

Then multiply the probabilities together.

Answer 4

my question shows the answer box as: P(red and yellow) ≈__________ %

Answer 5

nvm

Answer 6

i'll just guess

Answer 7

It is presented incorrectly, but it's not too bad. We can still work with it.
Answer the questions you have been presented.

Answer 8

Follow these steps:
A) Number of red marbles = ?
B) Total number of marbles before first drawing = ?
C) Divide number in A) by number in B)
D) Number of yellow marbles = ?
E) Total number of marbles left after first drawing = ?
F) Divide number in D) by number in E)
G) Multiply number in C) by number in F)
H) Your solution is the product in G)

Answer 9

No it is not it is 26%

Answer 10

@rayne612 be more nice when commenting, cause that offended me greatly

@Sworewolf The correct answer is 26% because 14/26 * 12/25 = 0.25846154. Sorry for my incorrect answer before.

Answer 11

I am sorry if I offended you, I didn't mean to in any way. I was just saying it was wrong. Sorry. Didn't mean ANY harm. Hope we're good! ;)

Answer 12

@Firejay5

Answer 13

we good lol computer communication is difficult to understand