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Mathematics 21 Online
OpenStudy (anonymous):

Function help? How do I solve this?

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

well for the restricted domain is the right hand part of the parabola [-3, oo)

OpenStudy (xapproachesinfinity):

let me show you the graph

OpenStudy (xapproachesinfinity):

http://prntscr.com/6rukzb

OpenStudy (xapproachesinfinity):

we will divide the graph to two and take the right part only [-3,oo) so our function will be one-to-one correspandance

OpenStudy (xapproachesinfinity):

so know we are ready to find the inverse function

OpenStudy (xapproachesinfinity):

start with f(x)=-(x+3)^2-4

OpenStudy (xapproachesinfinity):

are you even there, or you are the kind that awaits for the result and not putting effort I might be wrong, so prove me wrong and show me you are willing to solve this

OpenStudy (anonymous):

@xapproachesinfinity I'm here, just not staring at my question for an hour waiting for help, hang on

OpenStudy (xapproachesinfinity):

Ok put y=-(x+3)^2-4 \[\rm y=-(x+3)^2-4 \\ x=-(y+3)^2-4 ~~\longleftarrow ~switch~x~with~y~~~~ \]

OpenStudy (xapproachesinfinity):

then solve for y

OpenStudy (xapproachesinfinity):

\[\large \rm x+4=-(y+3)^2 \\ -(x+4)=(y+3)^2 \\ \sqrt{-(x+4)}=y+3~~here~x\ge-3 \] \[-3+\sqrt{-x-4}=y \Longrightarrow f^{-1}(x)=-3+\sqrt{-x-4}\]

OpenStudy (xapproachesinfinity):

I meant y>= -3 in the line 3 no x just to make things reasonable

OpenStudy (anonymous):

@xapproachesinfinity sorry kind of lost me

OpenStudy (bee_see):

are you having trouble with finding the inverse?

OpenStudy (bee_see):

|dw:1428639585992:dw|

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