Function help? How do I solve this?
well for the restricted domain is the right hand part of the parabola [-3, oo)
let me show you the graph
we will divide the graph to two and take the right part only [-3,oo) so our function will be one-to-one correspandance
so know we are ready to find the inverse function
start with f(x)=-(x+3)^2-4
are you even there, or you are the kind that awaits for the result and not putting effort I might be wrong, so prove me wrong and show me you are willing to solve this
@xapproachesinfinity I'm here, just not staring at my question for an hour waiting for help, hang on
Ok put y=-(x+3)^2-4 \[\rm y=-(x+3)^2-4 \\ x=-(y+3)^2-4 ~~\longleftarrow ~switch~x~with~y~~~~ \]
then solve for y
\[\large \rm x+4=-(y+3)^2 \\ -(x+4)=(y+3)^2 \\ \sqrt{-(x+4)}=y+3~~here~x\ge-3 \] \[-3+\sqrt{-x-4}=y \Longrightarrow f^{-1}(x)=-3+\sqrt{-x-4}\]
I meant y>= -3 in the line 3 no x just to make things reasonable
@xapproachesinfinity sorry kind of lost me
are you having trouble with finding the inverse?
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