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Chemistry 10 Online
OpenStudy (danise):

IN DESPERATE NEED!!! Please go step by step by using a calculator I know you have to use -log Calculate the [H+] of the following pH is: 7.662

OpenStudy (abb0t):

Anytime you see "\(p\)" next to something, for example \(p\)H that is just old fashioned notation meaning -log So, you know that pH = -log[H\(^+\)] remember from mathetmatics that in order to solve for something, you must raise both sides to the power of 10 to eliminate the log. Same with natural log, \(ln\), you can eliminate it by doing e\(^{ln(x)}\) = x the exponenential cancels out the natural log. So, if you have -log(x), you can do 10\(^{-log(x)}\) = -x So, if pH = - log[H\(^+\)], and if pH = 7.662 You would take do the exact same thing to eliminate the log and solve for H\(^+\)

OpenStudy (danise):

Thanks lol it really takes common sense lol

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