Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil. Jason decides to test the land for oil. He buys a kit that claims to have an 80% accuracy rate of indicating oil in the soil. If the test predicts that there is no oil, what is the probability after the test that the land has oil?
0.1698 0.2217 0.5532 0.7660
@YanaSidlinskiy
Again, let A=the land has oil B=the test says the land has oil we then want P(A|B)
What is the formula for P(A!B)
\[P(A|B)=\frac{P(A\cap B)}{P(B)}\]
Is that a*b/b?
well you can't multiply events like that, but no it is not the same as P(A)*P(B)/P(B)=P(A) because \(P(A\cap B)=P(A)P(B)\) if and only if A and B are independent, which they are not in this case since getting a positive test would change our expectation of finding oil
so again you will need to draw a tree
so its c
can you draw the tree
I don't know I haven't done the problem yet
well first we will need to draw the fork for A. Either the land has oil, or it does not|dw:1428685464403:dw|
given that the land has oil, the test has an 80% chance of saying that the land has oil, do the upper branch will look like so|dw:1428685556488:dw|(remember that B is the probability of getting a positive test for oil) so far so good?
so*
yesir
ok, so the lower branch corresponds to the event that there is no oil, in which case there is a 20% chance the test will say there is oil anyway. this gives us|dw:1428685675871:dw|
.8*.55?
which event does that correspond to?
80% positive
that is only half of the event you have described. you are describing this path on the tree|dw:1428685823655:dw|as you can see, this is the event that there is no oil on the land, and the test correctly indicates that.
.8*.45?
which event does that correspond to?
a and b
right, so where does that belong in our formula?
numerator
correct now for the denominator
.2*.45
we will again need the total probability theorem
what event is that?
my bad, .2*.55
ok, what does that represent though?
the fraction denominater
it's not the whole denominator, no that is only the event in which not A and B, which means you are trying to do we need the probability of only B on the bottom
which one is that??
\[P(A|B)=\frac{P(A\cap B)}{P(B)}\]how many ways can B occur?
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