How do I find function equations and graph those equations on a graph?
@Hoslos
This is an example of what I am asking.
Let me start by how to find equation, given the graph: One of the ways is to find the following in the graph: - The values cutting the x-axis - Any other point, which can also involve cutting the y-axis.
Taking your graph, - the x values are: -2 and 2 - Any other point: (0,1) The general formula to use is \[y=a(x-x_{1})(x-x _{2})\], where x1 and x2 are the x-values found. It does not matter which one comes first. Secondly, the any other point will be replaced in y and x, respectively. As you can see, the x appears twice and from the point, x=0 and y=1 \[1=a[0-(-2)](0-2)\]. You have everything except for a. That is what we have to find. The constant in this case. \[1=-4a\]\[a=-\frac{ 1 }{ 4 }\] Having found the constant, we rewrite the general formula, but now replacing only a and x1 and x2, finalizing the step \[y=a(x-x _{1})(x-x _{2})\] \[y=-\frac{ 1 }{ 4 }(x+2)(x-2)\] \[y=-\frac{ 1 }{ 4 }(x ^{2}-2x+2x-4)\] \[y=-\frac{ 1 }{ 4 }x ^{2} + 1\] There is the formula, basing from a point of the curve and the x values.
There is another way of doing this, which is by finding the ''other point'' and the vertex coordinate of the parabola. The original formula to use is \[y=a(x-p)+q\] where a is the constant, p and q are x and y values, respectively and y and x are the coordinates of the other point. The following step is two first replace all the values and you will be left with a to be found. Once you do that rewrite the formula, by only replacing the values of a, p and q , simplifying your equation. Unfortunately, this one can be manipulated under this method, because the vertex=other point. They should be different.
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