Convert 6+2i to Polar Form. Would love some steps!

Question

turingtest · Answer

can you draw this?

jhannybean · Answer

I'm not too familiar with imaginary sets, put do you remember your rules for converting from cartesian to polar coordinates?

jojokiw3 · Answer

Nope, I've never seen it before.

jojokiw3 · Answer

I usually see a "j" along with it.

turingtest · Answer

just draw a complex plane, which is a set of cartesian coordinates with the vertical axis labeled for the i-component|dw:1428692649926:dw|

jhannybean · Answer

For starters, all I remember learning was that: $x+yi = r$ 

and from previous math classes have learned that $r=\sqrt{x^2+y^2}$. Theta on the other hand, in polar coordinates, was equal to: $\theta =\tan^{-1}\left(\dfrac{y}{x}\right)$

That's all I know!

turingtest · Answer

yeah that is basically right
drawing the real and imaginary parts on the graph we get|dw:1428692811706:dw|we can draw a vector here...

jhannybean · Answer

Is this analogous to slopes?

turingtest · Answer

|dw:1428692891213:dw|yeah kinda. I mean all lines have slope stuff going on

jojokiw3 · Answer

6.32456 is the radius then at a 18.4349 angle?

turingtest · Answer

yeah, but I would convert the angle to radians

jojokiw3 · Answer

0.3217497019 radians.

turingtest · Answer

yes

jojokiw3 · Answer

Alright, gotcha. Thanks for the help. :)

turingtest · Answer

welcome!