What are the points of discontinuity?
y=((x+1)(x-5))/(x^2+4x+3)

Question

What are the points of discontinuity? 
y=((x+1)(x-5))/(x^2+4x+3)

lυἶცἶ0210 · Answer

Have you tried factoring?

anonymous · Answer

Like this? y=(x-5)/(x+3)

lυἶცἶ0210 · Answer

Yes, and what you elimated is where the discontinuity is

lυἶცἶ0210 · Answer

Just plug that x coordinate in to find y :)

anonymous · Answer

Oh! Okay that makes a lot more sense. So is it x=5 and x=-3?

lυἶცἶ0210 · Answer

Actually, when you factored, you got a common factor of x+1 right? Well solve that, x+1=0. So x= -1.

freckles · Answer

there is continuity when either factor of x^2+4x+3 is zero

freckles · Answer

you basically need to solve x^2+4x+3=0

freckles · Answer

you are already found one number such that y=f(x) is discontinuous

freckles · Answer

you just need to find the other

freckles · Answer

the types of discontinuity are different
the x=-1 you have a hole because (x+1)/(x+1)=1 when x isn't -1
the other discontinuity you have a vertical asymptote

lυἶცἶ0210 · Answer

Yea, whoops, sorry about the mix up ^

freckles · Answer

@FutureAnesthetist did you find the other discontinity?

anonymous · Answer

Yes, I got it! Thank you guys!

anonymous · Answer

Let me double-check real quick, it's x=-3, and x-1?

freckles · Answer

sounds beautiful