3. Light coming from a fish makes an incidence angle of 30° to normal under the water. The index of refraction of water is 1.33. A fisherman is looking at the fish through air. At what angle with the normal (θr) will the fish appear to the fisherman? Use Snell’s law: nisinθi = nrsinθr.
@funscience
HINT: The index of refraction for air is 1.00 (memorize this). Now solving this problem with Snell's Law should be easy!
yes, you can do it. Just plug in the given information.
recall that r is for refracted angle and i is for the incident angle.
i know ni is 1.33 and is nr 1? and i think 0i is 30 degrees
Can you post your calculations?
well i just figured that from the numbers given in the equation
Look at this: \[1.33 \sin30 =1\sin \theta \]\[\sin \theta=1.33\sin30\]\[\theta = \sin^{-1} (1.33\sin30)\]\[\theta = \space ?\]
you should always draw a diagram. it really helps
I can plug that into a scientific calculator to get the answer
I dont really know how to draw pictures for these types of problems
i got 0.01215
look at this diagram
make sure you're in degrees and not radians
do you know of a good website for a scietific calculator
you can download a scientific calculator on your phone. look at this file
oh okay those make it a little more clear
Im trying to get the answer now
I cant do it for some reason
you'll need to just do the calculations. @matt101 already gave you the derivation
so in the calculator i push sin the (1.33 sin) (30)?
no, you'll need to get the arcsin of 1.33sin30. so one the webcalc you'll have to press 2nd then asin
When i put it all in i got 30
i got 22 degrees
get yourself a calculator
that's all :D
I will lol thanks again :)
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