Question

The roots of the quadratic equation 2x^2+11x-40=0 are 2p and (q-2).Calculate the possible values of p and q.

Answer 1

@rational

Answer 2

start by finding the roots of given quadratic

Answer 3

see if it factors

Answer 4

\[2p+q-2=-\frac{ 11 }{ 2 }\]\[2p(q-2)=-20\]

Answer 5

Ahh nice you want to use sum of roots and product of roots

Answer 6

maybe plugin the value of "q-2" from first equation into second equation

Answer 7

\[2p(-\frac{ 11 }{ 2 })=-20\] like this? @rational

Answer 8

from the first equation we have
\[ q-2 = -\frac{11}{2}-2p\]

plugging this in second equation gives
\[2p(-\frac{11}{2}-2p) = -20\]

right ?

Answer 9

yup

Answer 10

\[-11p-4p^2=-20\]

Answer 11

\[-4p^2-11p+20=0\]\[4x^2+11x-20=0\]

Answer 12

p=5/4,-4

Answer 13

q=9/2,-6

Answer 14

Thnx @rational :)

Answer 15

looks perfect! yw :)

Answer 16

Ahh this reminds me of Vieta's Formula :)