Evaluate the radical expressions or indicate that the root is not a real number. ^3 sq root (-4)^3

Question

miracrown · Answer

$$\sqrt[3]{(-4)^{3}}$$

So it is a cube root? That's the part I'm unsure about
I assume ^3 sq root means cube root, but you never know

anonymous · Answer

Yes

miracrown · Answer

Okie... well, remember what a cube root is: In this case, they want:
"The number that, when we raise it to the 3rd power, we get (-4)^3"

So what do we have to raise the 3rd power, to get (-4)^3?

miracrown · Answer

$$?^{3} \space = (-4)^3$$

anonymous · Answer

I'm not sure! Would it be -2?

miracrown · Answer

It would actually be -4

You can think of it as the 3rd root and 3rd power (inside the root) "cancelling" each other

anonymous · Answer

Oh ok, I understand

anonymous · Answer

So would that be my answer?

miracrown · Answer

$$(-4)^3 = (-4)^3$$

Yep, that's what it boils down to! So the root itself is -4

miracrown · Answer

-4 is the answer here: It's the cube root of (-4)^3

anonymous · Answer

Thank you so much!

miracrown · Answer

You're welcum =]

anonymous · Answer

Can you help me with this one too? Solve the linear equation. 

2(x + 6) + 6 = 3(x + 5) + 7
  A. {6} 	
  B. {-4} 	
  C. {12} 	
  D. {9}

miracrown · Answer

Sure. What do we get if you distribute the 2's and the 3?