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Physics 23 Online
OpenStudy (anonymous):

2. What value did you calculate for the index of refraction of the acrylic block in Part 2? How does your value compare to the accepted value of 1.50? Calculate the percentage error. Different materials have distinct indexes of refraction. Explain how you might identify a material based on experiments like this one. Mention at least one of the difficulties in identifying materials based on their indexes of refraction.

OpenStudy (anonymous):

"What value did you calculate for the index of refraction of the acrylic block in Part 2?" Did you try the calculations in this activity? What did you get?

OpenStudy (anonymous):

I tried to do it but i didnt understand the experiemnt

OpenStudy (anonymous):

Sorry, I can't be of much help here. To answer this question you have to be able to get to the point where you calculate the value of the index of refraction.

OpenStudy (anonymous):

Well i did get a value of 2.31 when id did it could i use that?

OpenStudy (anonymous):

This value of n seems much too high for acrylic. Check your calculations.

OpenStudy (anonymous):

its suppose to be closer to 1.50? that's what i though but let me check my work

OpenStudy (anonymous):

I looked it over and I think that 1.64 is it @ghuczek

OpenStudy (anonymous):

@bohotness @danish071996

OpenStudy (anonymous):

@shamim

OpenStudy (anonymous):

@TuringTest @Nnesha @tkhunny @inkyvoyd

OpenStudy (bohotness):

yeessss

OpenStudy (anonymous):

can you help me please?

OpenStudy (bohotness):

yes

OpenStudy (anonymous):

do you want me to post the question again?

OpenStudy (bohotness):

i wil try and yes

OpenStudy (anonymous):

2. What value did you calculate for the index of refraction of the acrylic block in Part 2? How does your value compare to the accepted value of 1.50? Calculate the percentage error. Different materials have distinct indexes of refraction. Explain how you might identify a material based on experiments like this one. Mention at least one of the difficulties in identifying materials based on their indexes of refraction. I got 1.64 as my value

OpenStudy (bohotness):

:d and you tighy love xd

OpenStudy (anonymous):

what?

OpenStudy (bohotness):

rohgt

OpenStudy (anonymous):

can you help?

OpenStudy (bohotness):

yea

OpenStudy (anonymous):

yay great thanks so much lets get started xD lol

OpenStudy (bohotness):

XD

OpenStudy (anonymous):

so whats first?

OpenStudy (bohotness):

okay and your answer yyyou have is right

OpenStudy (anonymous):

how do i ccalcualte the percentage error?

OpenStudy (bohotness):

mhm

OpenStudy (anonymous):

??

OpenStudy (matt101):

You calculate it with the following equation: \[ percent \space error = {|actual-theoretical| \over theoretical} \times 100\]

OpenStudy (matt101):

Where "actual" is your measured value and "theoretical" is the value you expect it to be. The vertical lines in the equation mean you need to find the absolute value of the difference, so just take the positive of whatever number you get. And @bohotness...you ok? :P

OpenStudy (bohotness):

yes

OpenStudy (bohotness):

hy

OpenStudy (anonymous):

I got it thank you

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