Question

The temperature of a person with an extremely high fever can be lowered with a sponge bath of isopropyl alcohol (C3H7OH). The heat of vaporization of this alcohol is 11.1 kcal/mol.
(a) How many kilocalories and kilojoules of heat are removed from a person's skin when 177 g of isopropyl alcohol evaporates?

Correct: Your answer is correct.
kcal

Correct: Your answer is correct.
kJ
(b) How many kilograms of water would this energy loss cool in lowering the temperature from 47.4°C to 36.0°C?

_______ kg

Answer 1

@dtan5457

Answer 2

Okay so for Those correct answers, It was 32.68 kcal
and 136.73 kJ

Answer 3

Now i just need to solve for B

Answer 4

Trying to understand the problem..it's asking how much grams of water is needed to lower that temperature...but from what energy source...

Answer 5

What do you mean from what energy source?

Answer 6

I thought you solve this problem, you would just do Delta H = (m)(Cp)(Delta T)

Answer 7

oh yeah, you do. I got it now. I actually am being yelled at right now to wash the dishes...so...i'll be back in 15 min. give it a try in the mean time.

Answer 8

Than i just plugged in the numbers (177g)(4.184)(11.4)

Answer 9

okay

Answer 10

alright back

Answer 11

Wb i still can't solve this lmao

Answer 12

If 136.73 kJ was correct for your first question...

then you'd just do

136.73 kJ=(Mass)(11.4)(4.18) <<specific heat of water

Answer 13

Oh ! thank you

Answer 14

solved it?

Answer 15

yep

Answer 16

gooood job. still got any more questions or problems? i'll still be on for a bit

Answer 17

nah i finished! thank you though

Answer 18

Actually i have one more that my friend solved. But i dont know how to solve it

Answer 19

new question, tag :)