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How many grams of ice at 0°C and 101.3 kPa could be melted by the addition of 0.80 kJ of heat?
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@dtan5457
Pretty sure you just get the latent heat of fusion for water (333 j/g) then based on the formula of heat released/absorbed=latent heat x mass just plug everything in 0.8 kj=(333 j/g)(mass) solve for mass
you would definitely want to convert kj to joules first..
okay
i'm pretty sure the standard pressure here doesn't affect the question
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Thanks!
Where did the 333j/g come from?
reference table, lol. look for the fusion/vaporization section
oh lmao
yup. at least 50% of chemistry is all just looking at the reference table..
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