Question

The average value of a function f (x) on the interval [a, b] is A
Compute the average value of f (x) =
x^2 on [0, 3] and show that the area above y = A and below y = f (x) equals the area below y = A and above y = f (x).

Answer 1

@tkhunny

Answer 2

@Loser66

Answer 3

I don't understand the problem.

Answer 4

\[A= \frac{ 1 }{ b-a } \int\limits_{a}^{b} f(x) dx\]

Answer 5

ok, the average formula apply on [0,3] gives us y =A =3, right?

Answer 6

yes A=3

Answer 7

oh, I got it