Question

will fan+medal!! please check my work:

Answer 1

Question: Prove the Converse of the Pythagorean Theorem using similar triangles. The Converse of the Pythagorean Theorem states that when the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse, the triangle is a right triangle. Be sure to create and name the appropriate geometric figures.

Answer 2

my answer:

One triangle is labeled ABC, with b in the middle of AC, a in the middle of BC, and c in the middle of AB. Then we construct another triangle DFE with b in the middle of DF and a in the middle of FE.

If a2+b2=c2 then DABC is a right angled triangle with the right angle at C.


1. EF=BC=a and FD=CA=b Because DF is a right angle

2. EF=NC=a Angle F is a right triangle

3. FD=CA=b = given AB=c= square root of a2+b2 t

4. AB=DE
BC=EF
CA=FD By construction

5. Triangle ABC is congruent to triangle DEF by SSS.

Answer 3

Seems right to me

Answer 4

not trying to be mean or nothing but you responded in like 3 seconds after i posted it.. you obviously didn't read it :/

Answer 5

I have read it and it still seems right sorry

Answer 6

suuure

Answer 7

i really need to get this exam done so i really need answers. pls stop trying to fake me out and get me to fail

Answer 8

And sorry my computer is numb so it sent itself Sorry I usually have it copied ready to post after I read it if I think its correct, and I am not faking you

Answer 9

I promise

Answer 10

then wouldnt you have said that earlier..

Answer 11

I should have sorry Seems right to me

Answer 12

Ugh I hate this computer

Answer 13

okay, but im still getting a second opinion just to be sure

Answer 14

Thats fine I understand

Answer 15

@dan815 @Michele_Laino @amistre64 @wio

Answer 16

can you guys help me out?

Answer 17

I can prove your theorem using the first theorem of Euclide. Is it ok?

Answer 18

Euclide? im not familiar with that

Answer 19

either i wasnt taught it or i dont remember

Answer 20

can you still check it @Michele_Laino ?? im sorry its just math is really not my strong point

Answer 21

ok! I try

Answer 22

thank you so much you are a life saver

Answer 23

Please wait, I'm trying to write another proof to your theorem

Answer 24

sure thing. take your time

Answer 25

here is my proof:

Answer 26

let's consider a triangle whose edge satisfy the relationship:
\[{a^2} + {b^2} = {c^2}\]
nevertheless that's triangle is not a right triangle.
Namely I accept the hypotesis, and I deny the thesis

Answer 27

please tell me when I may continue

Answer 28

here is my triangle ABC:

Answer 29

furthermore let's suppose that the angle in C is greather than 90 degrees

Answer 30

@kaelro : "i really need to get this exam done so i really need answers. pls stop trying to fake me out and get me to fail"
ur not supposed to ask questions from an exam

Answer 31

So, I consider the mid point of the segment AB, and I call that point with M