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Consider an atom with the electron configuration of 1s22s22p63s2. Which successive ionization energy will be significantly higher than expected? A. First Ionization Energy B. Second Ionization Energy C. Third Ionization Energy D. Fourth Ionization Energy
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The element belongs to Group 2 in the periodic table and hence will have a significantly higher than expected value for the 3rd ionization energy as after losing two electrons from the 3s orbital it forms a stable electronic configuration which is similar to that of Neon.
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