Find the limit:
The limit of (d) of the complex number \[Z = \frac{ 1 }{ sind } + \frac{ 1 }{ cosd } i \] d -> pi/2 [No l'hopital]
Are you thinking guys or the question doesn't show ?
I was thinking, but now it seems you can just test the left and right hand limits and you sill see that the limit diverges
Clarify a bit
\[\large \lim_{d\to\pi/2^+}\frac1{\sin x}+\frac1{\cos x}i\\\large\lim_{d\to\pi/2^-}\frac1{\sin x}+\frac1{\cos x}i\]
What is x ? and I am still confused.
a typo, sorry\[\large \lim_{d\to\pi/2^+}\frac1{\sin d}+\frac1{\cos d}i\\\large\lim_{d\to\pi/2^-}\frac1{\sin d}+\frac1{\cos d}i\]
do you know how to take a right-handed limit?\[\large \lim_{d\to\pi/2^+}\frac1{\sin d}+\frac1{\cos d}i\]
Generally , I can. But in this one especially I can't.
what is the limit of sinx as x approaches pi/2 from the positive side?
sin(pi/2) = 1
sinx/x if x approaches 0 Ops !
sorry?
Hmmm , seems like I am lost , aren't I ?
perhaps lol do you know what a one-sided limit is?
Yeah, It's when a function approaches a point from right or left ( higher and lower values).
If that function has different left and right sided limits then It's limit doesn't exist.
Am I right or still lost ?
you are right, sorry i was distracted
so as x approaches pi/2 from the right, what value does sinx have? what about cosx?
You got the derivative ? " L'hopital rule" right ?
you don't want to use l'hospital, right?
Yep, written up !
I don't want "L'hospital rule" as It's higher than my grade , and each time I ask for limit they use it.
|dw:1428858939974:dw|here is a unit circle
as d approaches pi/2 from the right...|dw:1428859021838:dw|is sind positive or negative?
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