A railroad tunnel is shaped like a semiellipse as shown below. http://prntscr.com/6svnmp The height of the tunnel at the center is 58 ft and the vertical clearance must be 29 ft at a point 21 ft from the center. Find an equation for the ellipse.
yeah he is smart
ikr! rational
he's not on ;-; I thought of him
rational is smart too though :)
yeah.
let the equation of ellipse be \[\dfrac{x^2}{t} + \dfrac{y^2}{58^2}=1\] plugin the given point \((21, 29)\) in above equation and find the value of \(t\)
\(\dfrac{441}t +\dfrac{841}{3364}=1\) t = 588
Would I need to find the square root of t?
That looks good. sqrt is not needed, the equation of ellipse is \[\dfrac{x^2}{588} + \dfrac{y^2}{58^2}=1\]
Oh! Thanks :) Should I square 58 for the final answer?
yes above is the final equation of ellipse
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