A railroad tunnel is shaped like a semiellipse as shown below.
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The height of the tunnel at the center is 58 ft and the vertical clearance must be 29 ft at a point 21 ft from the center. Find an equation for the ellipse.
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OpenStudy (rational):
yeah he is smart
Nnesha (nnesha):
ikr! rational
OpenStudy (sleepyjess):
he's not on ;-;
I thought of him
OpenStudy (sleepyjess):
rational is smart too though :)
Nnesha (nnesha):
yeah.
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OpenStudy (rational):
let the equation of ellipse be \[\dfrac{x^2}{t} + \dfrac{y^2}{58^2}=1\]
plugin the given point \((21, 29)\) in above equation and find the value of \(t\)
OpenStudy (sleepyjess):
\(\dfrac{441}t +\dfrac{841}{3364}=1\)
t = 588
OpenStudy (sleepyjess):
Would I need to find the square root of t?
OpenStudy (rational):
That looks good. sqrt is not needed, the equation of ellipse is
\[\dfrac{x^2}{588} + \dfrac{y^2}{58^2}=1\]
OpenStudy (sleepyjess):
Oh! Thanks :) Should I square 58 for the final answer?
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