Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 4 = 0

I know the discriminant is -12, but how do I find the rest?

Answer 1

use it to determine how many real-number roots the equation has) is the part I am confused about

Answer 2

Discriminant: \(\sf\Large b^2-4ac\)

Where the equation is: \(\sf\Large ax^2+bx+c=0\)

Answer 3

\(\sf\Large b^2-4ac >0\)

Then there are \(\bf\color{red}{2~real~roots!}\)

Answer 4

\(\sf\Large b^2-4ac =0\)

Then there are \(\bf\color{red}{1~real~roots!}\)

Answer 5

\(\sf\Large b^2-4ac <0\)

Then there are \(\bf\color{red}{2~complex~roots!}\)

Answer 6

Then there are two complex roots. Is that my answer?

Answer 7

Oh wait!

Answer 8

No there is 1 Real root so that is my answer

Answer 9

Okay thank you @TheSmartOne

Answer 10

There are 0 real roots, and 2 complex roots.

Complex roots have \(\sf i\) in them. It's called imaginary roots.

Answer 11

Oh

Answer 12

Okay. Thank you again

Answer 13

:)