3 C2H5OH + PCl3 → 3 C2H5Cl + H3PO3If a chemist starts with 105.0 g of ethanol and 135.65 g of phosphorus trichloride, then what is the limiting reagent?
I converted the ethanol and the phosphorus trichloride to moles...2.279 mol and .987mol respectively.....do I need to consider the products part of the equation to find the limiting reagent?
No, you need to make two ratios to determine which is going to be your excess and limiting reactant, I'm going to assume your moles are correct.
One ratio is the "problem ratio", the one given in the problem (where you had to convert the ratio) 2.279/.987=2.309 then you need to make one for the equation ratio (the one given in your balanced equation) 3/1=3 equation ratio> problem ratio denominator is excess, and numerator is limiting so ethanol is limiting reactant
Join our real-time social learning platform and learn together with your friends!