Question

A basket contains the following pieces of fruit 3 apples 2 oranges 2 bananas 2 pears and 5 peaches. Jamson picks a fruit at random and does not replace it. Then Brittany picks a fruit at random. What is the probability that Jameson gets a banana and Brittany gets a pear?

Answer 1

Find the probability of each drawing, then multiply them together.

Answer 2

For the first drawing, you want a banana.
How many bananas are there? How many pieces of fruit are there in total?

Answer 3

14 pieces of fruit .. total

Answer 4

Right. How many bananas?

Answer 5

2 bananas

Answer 6

Right.
We can now do the probability of the first drawing.
Probability of picking a banana in the first drawing is
P(banana) = 2/14 = 1/7

Answer 7

Ok?

Answer 8

ok thank you

Answer 9

We're not done yet.

Answer 10

ok

Answer 11

The second pick is a pear.
Now we need to see what is the probability of picking a pear in the second drawing.

Answer 12

ok

Answer 13

There were 14 pieces of fruit at the beginning.
A banana has been taken and has not been replaced.
How many pieces of fruit are there now before the second drawing?

Answer 14

13

Answer 15

Good.
There are still 2pears, so the probability of picking a pear in the second drawing is:
P(pear) = 2/13

Answer 16

right ok

Answer 17

The probability of picking a banana followed by a pear is the product of the two probabilities:

P(banana followed by pear) = P(banana) * P(pear) = 1/7 * 2/13 = 2/91

Answer 18

The final answer is 2/91

Answer 19

thanks

Answer 20

You're welcome.