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Mathematics 16 Online
OpenStudy (anonymous):

if cos Ⓗ= -4/7 , what are the values of sin Ⓗ and tan Ⓗ ? help step by step!

OpenStudy (turingtest):

what does cosine represent (in terms of opposite, adjacent, hypotenuse)

OpenStudy (anonymous):

i know that the formula is cos(0)=adjacent/hypotenus

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

correct, so that means we can draw a picture|dw:1428868205437:dw|now you can fill in the values for the sides

OpenStudy (anonymous):

what do you mean by fill the values?

OpenStudy (turingtest):

well if cos Ⓗ= -4/7=adjacent/hypotenuse, how long is the adjacent?

OpenStudy (anonymous):

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhh do i divie the adjacent and the hypotenuse?

OpenStudy (anonymous):

divide*

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

no you need to label the picture

OpenStudy (turingtest):

\[\cos\theta=-\frac47=\frac{adjacent}{hypotenuse}\]

OpenStudy (turingtest):

how long is the adjacent?

OpenStudy (anonymous):

oh i get it i subtract the adjacent from the hypotenuse

OpenStudy (turingtest):

you have to use the pythagorean theorem

OpenStudy (anonymous):

isnt the hypotenuse= to the adjacent and opposite added up together?

OpenStudy (anonymous):

oh so a^2+b^2=c^2 ?

OpenStudy (turingtest):

yep

OpenStudy (anonymous):

give me a second

OpenStudy (anonymous):

a^2 + b^2 = c^2 -4^2 + 7^2 = c^2 16 + 49 = c^2 16 + 49 = 65

OpenStudy (anonymous):

but for the 65 since its still like to the second power, do i square root it? or divide it by 2 ?

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

not quite, a is the opposite side, b is the adjacent side, and c is the hypotenuse

OpenStudy (anonymous):

im confused , can you illustrate this for me ?

OpenStudy (turingtest):

well again, look at the formula\[\cos \theta= -\frac47=\frac{adjacent}{hypotenuse}\]how long is the adjacent?

OpenStudy (anonymous):

-4?

OpenStudy (turingtest):

you can ignore the minus sign, so just 4, yeah so put this on the picture|dw:1428869526075:dw|how long is the hypotenuse?

OpenStudy (anonymous):

7?

OpenStudy (anonymous):

but what about the negative sign ?

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

that tells you what quadrant you are in. |dw:1428869832426:dw|because the adjacent is negative we know we must be in either quadrant II or III. however this doesn't really matter for us, we just need the lengths of the triangle sides and can figure out the quadrant stuff later.

OpenStudy (anonymous):

so the adjacent is 4 and the hypotenuse is 7?

OpenStudy (turingtest):

yes|dw:1428870265584:dw|so now go back to the pythagorean theorem: \[a^2+b^2=c^2\\a=\sf adjacent\\b=\sf opposite\\c=\sf hypotenuse\]

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