if cos Ⓗ= -4/7 , what are the values of sin Ⓗ and tan Ⓗ ? help step by step!
what does cosine represent (in terms of opposite, adjacent, hypotenuse)
i know that the formula is cos(0)=adjacent/hypotenus
@TuringTest
correct, so that means we can draw a picture|dw:1428868205437:dw|now you can fill in the values for the sides
what do you mean by fill the values?
well if cos Ⓗ= -4/7=adjacent/hypotenuse, how long is the adjacent?
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhh do i divie the adjacent and the hypotenuse?
divide*
@TuringTest
no you need to label the picture
\[\cos\theta=-\frac47=\frac{adjacent}{hypotenuse}\]
how long is the adjacent?
oh i get it i subtract the adjacent from the hypotenuse
you have to use the pythagorean theorem
isnt the hypotenuse= to the adjacent and opposite added up together?
oh so a^2+b^2=c^2 ?
yep
give me a second
a^2 + b^2 = c^2 -4^2 + 7^2 = c^2 16 + 49 = c^2 16 + 49 = 65
but for the 65 since its still like to the second power, do i square root it? or divide it by 2 ?
@TuringTest
not quite, a is the opposite side, b is the adjacent side, and c is the hypotenuse
im confused , can you illustrate this for me ?
well again, look at the formula\[\cos \theta= -\frac47=\frac{adjacent}{hypotenuse}\]how long is the adjacent?
-4?
you can ignore the minus sign, so just 4, yeah so put this on the picture|dw:1428869526075:dw|how long is the hypotenuse?
7?
but what about the negative sign ?
@TuringTest
that tells you what quadrant you are in. |dw:1428869832426:dw|because the adjacent is negative we know we must be in either quadrant II or III. however this doesn't really matter for us, we just need the lengths of the triangle sides and can figure out the quadrant stuff later.
so the adjacent is 4 and the hypotenuse is 7?
yes|dw:1428870265584:dw|so now go back to the pythagorean theorem: \[a^2+b^2=c^2\\a=\sf adjacent\\b=\sf opposite\\c=\sf hypotenuse\]
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