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Mathematics 19 Online
OpenStudy (anonymous):

PLEASE....Nicole missed the lesson on normal distribution and needs to do her homework. Explain to Nicole how to use the mean and standard deviation of a normal distribution to determine the top 5% of the population.

OpenStudy (amistre64):

does the nichole, or the person explaining to her ... know what a z score is?

OpenStudy (amistre64):

some texts call it a "standard" score

OpenStudy (anonymous):

Well I have this down in my asnwer box... "Using the Z chart I have to find the number for 0.05 which is .95053 and slide over to get 1.6. So it becomes 1.65. "

OpenStudy (amistre64):

thts almost coherent, but lacks a little

OpenStudy (amistre64):

what do we use the Zchart for? and how do we use it?

OpenStudy (anonymous):

We use the Z chart for idk

OpenStudy (amistre64):

then your explanation doesnt mean anything ...

OpenStudy (amistre64):

can you tell me what a zchart looks like?

OpenStudy (anonymous):

Well I know that we need it for this formula x=x-mean/sigma

OpenStudy (amistre64):

it would be nice to know and have i agree, and this question assumes that your lessons have covered it and is assessing your understanding of it.

OpenStudy (anonymous):

I have it printed it has 0.0-3.9 on the left side and at the top it has .00-.09 and there is numbers throughout it

OpenStudy (amistre64):

the top and left sides are the zscore, split up say z = 2.35 row 2.3 and col .05 cross in the middle at some .xxxx value what is the value related to z=1.26?

OpenStudy (anonymous):

..89617

OpenStudy (amistre64):

good, then we know how to read it ... 8962 is what i see in mine

OpenStudy (amistre64):

now, look in the middle for a number that is close to .9500 we are going to work the table from the inside out

OpenStudy (anonymous):

1.65 which is what I said

OpenStudy (anonymous):

the value is .95053

OpenStudy (amistre64):

1.65 is fair, but ... notice that 1.64 and 1.65 and .9500 exactly in the middle so we would want to use the average of them. i think thats the only one that happens on. but either way, 1.65 is fair for this

OpenStudy (amistre64):

you did not explain very well how we get the z score, which is why we covered this

OpenStudy (amistre64):

Using the Zchart, find the field value closest to .9500 (why?) becuase our top 5% is a right tail and we are using a left tail chart. left tail value is 1 - .05 = .95 now work the z formula backwards z = (x-mean)/sd solve for x since everything else is known

OpenStudy (anonymous):

How is the mean and standard deviation known?

OpenStudy (amistre64):

.... they are stated in the information inthe problem of course

OpenStudy (amistre64):

or at least they were the last time i worked this thing

OpenStudy (anonymous):

I didnt mean that

OpenStudy (amistre64):

at any rate, if we know the mean and sd, plug them in to determine the value of x z = (x-mean)/(sd) how do we solve for x?

OpenStudy (anonymous):

1.65=(x-mean)/(sd) I dont know actually

OpenStudy (amistre64):

its a basic algebra problem now .... how do we solve for an unknown? we get it all by itslef on one side

OpenStudy (anonymous):

multiply

OpenStudy (amistre64):

good 1.65(sd) = x - mean then ...

OpenStudy (anonymous):

subtract x from mean and cancel it out?

OpenStudy (amistre64):

um, add the mean to both sides to get x all alone 1.65(sd) + mean = x - mean + mean 1.65(sd) + mean = x

OpenStudy (anonymous):

oh yeah my bad

OpenStudy (anonymous):

Okay totally makes sense

OpenStudy (amistre64):

:) good luck

OpenStudy (amistre64):

most of the other people in here didnt know what or how to find a zscore; which of course makes the problem way more difficult then it has to be.

OpenStudy (anonymous):

Okay thank you, if I open another question will you help me with it?

OpenStudy (amistre64):

im going to be preoccupied, but theres plentyon here that are good at this stuff. theyll repsond.

OpenStudy (amistre64):

they may even be able to type better

OpenStudy (anonymous):

Ok thanks again!!!

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