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Find the limit as arctan(2n/ (2n+1)) when n approaches infinity.
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?
\[\lim_{2n\to \infty}\frac{2n}{2n+1}=1\]
But it is arctan?
yes and artan is a continuous function
I'm sorry, but how does the relate? :)
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that*
making your answer \[\arctan(1)\]
So we are able to find the limit of the inner function then apply the outer function to the result of the inner limit?
yes, if it is continuous
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