Find the sum of this infinite series.
=3^(1/n)
Would this be a geometric series?
are you sure you are suppose to find the sum? Or determine if it converges or diverges?
Well if it diverges or converges.
How could you determine if it converges without finding the value?
there are tests you can perform
like root test, ratio test, and so on...
see what happens if you look at \[\lim_{n \rightarrow \infty} \sqrt[n]{3}\]
if this doesn't equal 0 you can certain say \[\sum_{n=1}^{\infty}\sqrt[n]{3}\] diverges (this is my the divergence test)
that is only if that limit isn't 0
so let me know what you get for that limit
1, which is not 0. Thus it is divergent.
@freckles Why is this true though? How does this rule work?
(I know this rule from learning it previously in class, but how does it work?)
can we sat u = 1/n ?
state? sure
when n=1, u=1 when n=infinity, u = 0 maybe lol
http://tutorial.math.lamar.edu/Classes/CalcII/ConvergenceOfSeries.aspx I don't know if paul explains it here or not but these are definitely my choice of notes for calculus
Okay, I'll make sure to read those through @freckles
http://www.wolframalpha.com/input/?i=%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+3%5E%281%2Fn%29 just so we dont try to find a sum that isnt there :)
:)
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