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Mathematics 10 Online
OpenStudy (anonymous):

Find the sum of this infinite series.

OpenStudy (anonymous):

OpenStudy (anonymous):

=3^(1/n)

OpenStudy (anonymous):

Would this be a geometric series?

OpenStudy (freckles):

are you sure you are suppose to find the sum? Or determine if it converges or diverges?

OpenStudy (anonymous):

Well if it diverges or converges.

OpenStudy (anonymous):

How could you determine if it converges without finding the value?

OpenStudy (freckles):

there are tests you can perform

OpenStudy (freckles):

like root test, ratio test, and so on...

OpenStudy (freckles):

see what happens if you look at \[\lim_{n \rightarrow \infty} \sqrt[n]{3}\]

OpenStudy (freckles):

if this doesn't equal 0 you can certain say \[\sum_{n=1}^{\infty}\sqrt[n]{3}\] diverges (this is my the divergence test)

OpenStudy (freckles):

that is only if that limit isn't 0

OpenStudy (freckles):

so let me know what you get for that limit

OpenStudy (anonymous):

1, which is not 0. Thus it is divergent.

OpenStudy (anonymous):

@freckles Why is this true though? How does this rule work?

OpenStudy (anonymous):

(I know this rule from learning it previously in class, but how does it work?)

OpenStudy (amistre64):

can we sat u = 1/n ?

OpenStudy (anonymous):

state? sure

OpenStudy (amistre64):

when n=1, u=1 when n=infinity, u = 0 maybe lol

OpenStudy (freckles):

http://tutorial.math.lamar.edu/Classes/CalcII/ConvergenceOfSeries.aspx I don't know if paul explains it here or not but these are definitely my choice of notes for calculus

OpenStudy (anonymous):

Okay, I'll make sure to read those through @freckles

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+3%5E%281%2Fn%29 just so we dont try to find a sum that isnt there :)

OpenStudy (anonymous):

:)

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