Solve the absoulte value inequailty below, expressing your answer in interval notation.
\[\frac{ 1 }{ \left| x+5 \right| }\ge1\]
I've gotten as far as \[-4\ge x\]
and \[-6\le x\]
the problem is that I can't figure out how to write my answer in interval notation
\[-6 \le x \le -4\]
I've gotten it that far, but interval notation is (?,?) or [?,?] or something similar.
oh right sorry
square brackets if it's less than/ greater than and equal to. round brackets if it's not equal to.
< and > are round brackets, \[\le and \ge \]
* are square brackets
So what should the answer be?
[-6,-4] is what I've come up with, but my online program says that is incorrect.
Well that is in interval notation. are you sure -6, -4 is correct?
Yes
Notice that the expression becomes undefined when \(x=-5\), so you need to exclude it from solution
the solution after excluding would be \[\large [-6,-5) \cup (-5, -4]\]
Thank you! I had tried a similar answer earlier but I must have used the wrong type of brackets.
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