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Chemistry 10 Online
OpenStudy (bloomlocke367):

in which direction will the following reaction go if the standard reduction potentials are 0.80 V for Ag/Ag+ and -0.44 V for Fe/Fe2+?

OpenStudy (bloomlocke367):

@JFraser

OpenStudy (jfraser):

which reduction potential is larger?

OpenStudy (bloomlocke367):

Silver?

OpenStudy (jfraser):

then the silver will be the reduction half, and the iron will be flipped backwards and be the oxidation

OpenStudy (bloomlocke367):

So does that mean it's a reverse reaction?

OpenStudy (jfraser):

it means that iron won't be reduced, because its potential is lower than the reduction potential of silver

OpenStudy (jfraser):

you can use the half-reactions to write the overall reaction once you know that

OpenStudy (bloomlocke367):

Well the reaction is \(Ag^++Fe--->Ag+Fe^{2+}\)

OpenStudy (bloomlocke367):

oh, that's not a minus sign by the way...

OpenStudy (jfraser):

ok, so look at the silver in the reaction. Is it being oxidized, or reduced?

OpenStudy (jfraser):

it goes from \(Ag^{+1}\) to \(Ag^0\). Is that oxidizing (losing electrons) or reducing (gaining electrons)

OpenStudy (bloomlocke367):

reducing, right?

OpenStudy (jfraser):

it is.

OpenStudy (jfraser):

since the way the forward reaction is written shows silver being reduced, and silver has a higher reduction potential than iron, then the reaction will run in the direction that \(favors\) the highest reduction potential

OpenStudy (bloomlocke367):

so what's the highest reduction potential? (I'm sorry for so many questions)

OpenStudy (jfraser):

which has the higher reduction potential: silver, or iron?

OpenStudy (bloomlocke367):

silver.

OpenStudy (jfraser):

so the reaction will run in the direction where silver gets reduced

OpenStudy (bloomlocke367):

ohh where it gets reduced. So it's a forward reaction? because it's reduced in the product side?

OpenStudy (jfraser):

because silver gets reduced in the forward direction, that's the direction the reaction will run in

OpenStudy (bloomlocke367):

okay, thank you so much!

OpenStudy (bloomlocke367):

One more?

OpenStudy (jfraser):

sure

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